Answer:
See below.
Step-by-step explanation:
Arranging the data in ascending order:
Team one: { 47, 49, 51, 53, 54, 54, 57, 59, 60, 62}
Team two: {43, 48, 49, 51, 52, 53, 56, 57, 61, 63}
The mean for team one = sum of the scores / 10 =
= 546/10 = 54.6.
The median for team 1 = 54.
The mean for team two = sum of the scores / 10 =
= 533/10 = 53.3.
The median for team 2 = 52.5.
Team 1 has a higher mean than team 2: 54.6 - 53.3 = 1.3 higher.
In both cases, the mean is greater than the median though the difference is < 1 in both cases. So in both cases the distribution of the scores is close to symmetrical, with team 1 being slightly more symmetrical.
