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Find δg o for the following reaction, using δh o f and s o values. H2(g) i2(s) → 2 hi(g)

Sagot :

The  standard change in free energy is -35.76 kJ/mol. Values of standard free energy are obtained from thermodynamic tables.

What is the standard change in free energy?

The standard change in free energy can  be obtained using the relation;

ΔG°= ΔH° - TΔS

When;

ΔH°f(HI) = 26.466 kJ/mol

ΔH°f(H2) = 0 kJ/mol

ΔH°f(I2) = 0 kJ/mol

ΔS°f(HI) = 221.63 J/K/mol

ΔS°f(H2) = 145.64 J/K/mol

ΔS°f(I2) = 0 J/K/mol

Hence;

ΔH°freaction = [ 2(26.466)] - 0

= 52.932 kJ/mol

ΔS°freaction = [2(221.63 ) ] - [145.64 + 0]

= 443.26 - 145.64 = 297.62 J/K/mol

ΔG°= 52.932 * 10^3 - [298 * 297.62 ]

ΔG°= -35.76 kJ/mol

The  standard change in free energy is -35.76 kJ/mol.

Learn more about change in free energy: https://brainly.com/question/14143095

The change in free energy for the given chemical reaction between hydrogen and iodine gas is -31.068 kJ/mol.

How do we calculate the free energy change?

Free energy change of any reaction will be calculated by using the below equation:

ΔG° = ΔH° - TΔS, where

ΔH° = change in enthalpy

T = absolute temperature = 298K

ΔS = change in entropy

Change in any quantity during the reaction will be find out by substracting the reactant values from product values.

Given chemical reaction is:

H₂(g) + I₂(g) → 2HI(g)

ΔH° = 2(26.466)] - 0 = 52.932 kJ/mol

ΔS = [2(206.6) ] - [131 + 0] = 413.2 - 131 = 282.2 J/K.mol = 0.282 kJ/K.mol

On putting values on above equation, we get

ΔG° = 52.932 - (298)(0.282) = -31.068 kJ/mol

Hence required free enrgy is -31.068 kJ/mol.

To know more about free energy change, visit the below link:

https://brainly.com/question/7600523

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