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Sagot :
The rotational inertia about an axis tangent to the sphere of the given mass and radius is ⁷/₅MR².
Parallel axis theorem
According to parallel axis theorem, the moment of inertia of a body about any axis is equal to the sum of the product of its mass and the square of the distance between the two parallel axis and the moment of inertia of the body about a parallel axis passing through its centre of mass.
The moment of inertia of the sphere about its parallel axis passing through its centre of mass = ²/₅MR²
The product of its mass and the square of the distance between the two parallel axis = MR²
Rotational inertia about an axis tangent to the sphere
Moment of inertia about an axis tangent to the sphere = MR² + ²/₅MR²
= ⁷/₅MR²
Learn more about moment of inertia here: https://brainly.com/question/3406242
The rotational inertia of a sphere of given mass and radius along a tangent axis is [tex]\rm \frac{7}{5} MR^2[/tex].
What is a moment of inertia?
The sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation expresses a body's tendency to resist angular acceleration.
The given data in the problem is;
M is the sphere's mass.
R is the radius of a sphere
According to the parallel axis theorem,The rotational inertia of a sphere of given mass and radius along a tangent axis is found as;
[tex]\rm I=MR^2+\frac{2}{5} MR^2 \\\\ I=\frac{7}{5} MR^2[/tex]
To learn more about the moment of inertia refer to the link;
https://brainly.com/question/15246709
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