IDNLearn.com offers a comprehensive platform for finding and sharing knowledge. Find the solutions you need quickly and accurately with help from our knowledgeable community.
Sagot :
Answer: [tex]3.45*10^{-7}[/tex]
Explanation:
we can use the equation Ka * Kb = Kw
Kw is the equilibrium constant and always equals to [tex]1*10^{-14}[/tex]
we plug the given numbers into the equation, [tex]Ka * (2.9*10^{-8} )=(1*10^{-14} )[/tex]
now we just solve for Ka, [tex]Ka=\frac{1*10^{-14} }{2.9*10^{-8} }[/tex]
which gives us the value, [tex]Ka=3.45*10^{-7}[/tex]
hope this helped! ♡
The ka of the weak acid ha, whose conjugate base has kb 2. 9 × 10⁻⁸ is 3.45 × 10⁻⁷.
What is ka value?
Ka value is the equilibrium constant found by the dissociation of acid.
By the equation
[tex]\rm ka \times kb = kw[/tex]
where kb = [tex]2.9 \times 10^-^8[/tex]
kw = [tex]1 \times 10^-^4[/tex]
Now, putting the values in the equation
[tex]1 \times 10^-^1^4 = ka \times 2.9 \times 10^-^8\\\\ka = \dfrac{1 \times 10^-^1^4}{2.9 \times 10^-^8} \\\\ka = 3.45 \times 10^-^7[/tex]
Thus, the ka of the weak acid ha, whose conjugate base has kb 2. 9 × 10⁻⁸ is 3.45 × 10⁻⁷.
Learn more about ka values
https://brainly.com/question/2796803
#SPJ4
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and come back for more insightful information.