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The null hypothesis is a general statement. According to this, there is no relationship between two phenomena under consideration. Here the p value will be 0.1086. As the P-value is greater so it was is rejected.
It is an alternative hypothesis that describes that there is a relationship between two selected variables in a study.
To test for the evidence of a difference in mean b loss for the two methods done by null and alternative hypothesis.
Its given that
Sample mean x = -2
Population mean = 0SD = 6
Sample size n = 25
According to t-test statistics
[tex]t=\frac{x-\mu }{\frac{\sigma}{\sqrt{n} } }[/tex]
[tex]t=\frac{-2-0}{\frac{6}{\sqrt{25} }}[/tex]
t=-1.667
P-value = P(t ≤ -1.667) + P(t ≥ 1.667)
P-value = 0.1086
Thus, as the P-value is greater than It is subjected for rejection.
For more information regarding null and alternative hypotheses, visit:
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