Dive into the world of knowledge and get your queries resolved at IDNLearn.com. Our platform is designed to provide reliable and thorough answers to all your questions, no matter the topic.
For ksp of silver sulfate (ag2so4) at 1. 2 ✕ 10-5, the solubility of silver sulfate is mathematically given as
x = 5.26*10^{-4}
Generally, the equation for the Chemical reaction is mathematically given as
Ag2SO4 ⇄ 2Ag+ + SO4 2-
Therefore
Ksp = [Ag+ ]2 *[SO4 2-]
1.2*10-5 = ( 0.15 +2x)2*(x)
x = 5.26*10^{-4}
In conclusion, the solubility of silver sulfate is
x = 5.26*10^{-4}
Read more about Chemical reaction
https://brainly.com/question/16416932
If the ksp of silver sulfate (ag2so4) at 1.2 × 10⁻⁵, the solubility of silver sulfate is 5.26 × 10⁽⁻⁴⁾.
ksp value determines the equilibrium between the solids and its respective ions in a solution.
The reaction is [tex]\rm Ag_2SO_4 \leftrightharpoons 2Ag+ + SO_4^2-[/tex]
The ksp pf silver sulfate is 1.2 × 10⁻⁵
Tho calculate the solubility?
Putting the values in the equation
[tex]\rm Ksp = [Ag^+ ]^2 \times [SO_4^ 2^-]\\\\1.2\times 10^-^5 = ( 0.15 +2x)2\times (x)\\x = 5.26\times 10^{-4}[/tex]
Thus, the solubility of silver sulfate is 5.26 × 10⁽⁻⁴⁾.
Learn more about silver sulfate
https://brainly.com/question/17094293
#SPJ4