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The molar solubility of Ba₃(PO₄)₂ is its concentration of pure substance
The correct equation for the ksp is Ksp = 6x⁵
How to determine the equation of ksp?
Start by writing the reaction for the solution of Barium phosphate
Ba₃(PO₄)₂ ⇌3Ba²⁺ +2PO₄³⁻
Next, we make an ICE chart
Let "x" be the molar solubility of Barium phosphate
Ba₃(PO₄)₂(s) ⇌3Ba²⁺ +2PO₄³⁻
I 0 0
C +3x +2x
E 3x³ 2x²
Lastly, we write the expression for the solubility product constant (Ksp)
This is represented as:
Ksp = [3Ba²⁺] × [2PO₄³⁻]²
Ksp = 3x³ × 2x²
Evaluate the product
Ksp = 6x⁵
Hence, the correct equation for the ksp is Ksp = 6x⁵
Read more about molar solubility at:
https://brainly.com/question/9732001
The molar solubility of Ba₃(PO₄)₂ is its concentration of a pure substance.
The correct equation for the ksp is Ksp = 6x⁵.
How to determine the equation of ksp?
The solubility product constant is the equilibrium constant for the dissolution of a solid substance into an aqueous solution. It is denoted by the symbol Ksp.
Start by writing the reaction for the solution of Barium phosphate.
Ba₃(PO₄)₂ ⇌3Ba²⁺ +2PO₄³⁻
Let "x" be the molar solubility of Barium phosphate
Ba₃(PO₄)₂(s) ⇌3Ba²⁺ +2PO₄³⁻
I 0 0
C +3x +2x
E 3x³ 2x²
Lastly, we write the expression for the solubility product constant (Ksp),
This is represented as:
Ksp = [3Ba²⁺] × [2PO₄³⁻]²
Ksp = 3x³ × 2x²
Evaluate the product
Ksp = 6x⁵
Hence, the correct equation for the ksp is Ksp = 6x⁵
Read more about molar solubility at:
brainly.com/question/9732001
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