IDNLearn.com connects you with a global community of knowledgeable individuals. Discover detailed and accurate answers to your questions from our knowledgeable and dedicated community members.
Sagot :
The required equation f(10) = 13.52 mg remains.
We have given that ,
m is the initial mass and h is the half-life in years. cobalt-60 has a half-life of about 5.3 years. which equation gives the mass of a 50 mg cobalt-60
What is the fromula for he amount of a radioactive substance remaining after t years?
The amount of a radioactive substance remaining after t years is given by the function
[tex]f(t)=m(0.5)^{t/h}[/tex]............ (1),
where m = initial mass and h= half-life in years.
Now, for Cobalt-60, h = 5.3 years, m = 50 mg and t = 10 years,
then from equation (1) we get,
[tex]f(10)=50(0.5)^{10/5.3}[/tex]
Therefore the required equation f(10) = 13.52 mg .
To learn more about the mass of radioactive substance visit:
https://brainly.com/question/25793075
Answer:
The required equation f(10) = 13.52 mg remains.
We have given that ,
m is the initial mass and h is the half-life in years. cobalt-60 has a half-life of about 5.3 years. which equation gives the mass of a 50 mg cobalt-60
What is the fromula for he amount of a radioactive substance remaining after t years?
The amount of a radioactive substance remaining after t years is given by the function
............ (1),
where m = initial mass and h= half-life in years.
Now, for Cobalt-60, h = 5.3 years, m = 50 mg and t = 10 years,
then from equation (1) we get,
Therefore the required equation f(10) = 13.52 mg .
To learn more about the mass of radioactive substance visit:
brainly.com/question/25793075
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com has the solutions you’re looking for. Thanks for visiting, and see you next time for more reliable information.
