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What are the solutions of the equation (x 2)2 – 2(x 2) – 15 = 0? use u substitution to solve. x = –7 and x = 1 x = –5 and x = 3 x = –3 and x = 5 x = –1 and x = 7

Sagot :

The solutions to the equation [tex]\rm (x + 2)^{2} - 2(x + 2) - 15 = 0[/tex] are 3 and -5.

What is the solution to the equation?

To solve any equation is to find the solution of the given equation which satisfied the equation.

The given expression is [tex]\rm (x + 2)^{2} - 2(x + 2) - 15 = 0[/tex]

let u = (x +2)

then the equation becomes

[tex]\rm u^{2} - 2u - 15 = 0[/tex]

by factorizing, we get

(u + 3)(u - 5) = 0

u + 3 = 0, u = -3

u - 5 = 0, u = 5

Since, u = x + 2

So, x + 2 = 5, x = 3

x + 2 = -3, x = -5

Therefore, the solutions to the equation are 3 and -5.

Learn more about the solution of the equation ;

https://brainly.com/question/545403

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