Answered

Ask questions, share knowledge, and connect with a vibrant community on IDNLearn.com. Our community is here to provide detailed and trustworthy answers to any questions you may have.

A car of 15 kg is traveling on a circular track. If the radius of the track is

7. 8 m and the period is 8. 5 seconds, what's the centripetal force on

the car? (Round to the nearest hundredth)

Sagot :

Asuwafohjamesidn

The magnitude of the centripetal force on the car is 69.6 N.

What is centripetal force?

This is a force acting on a body in circular path and it is directed to the center around which the body is moving.

To calculate the centripetal force on the car, we use the formula below.

Formula:

  • F = m(4π²/t²)........ equation 1

Where:

  • F = Magnitude of the centripetal force on the car,
  • m = mass of the car
  • t = time

From the question,

Given:

  • m = 15 kg
  • t = 8.5
  • π = 3.14

Substitute these values into equation 1

  • F = 15(4×3.14²/8.5²)
  • F = 69.6 N

Hence, the magnitude of the centripetal force on the car is 69.6 N.

Learn more about centripetal force here: https://brainly.com/question/20905151

Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. IDNLearn.com provides the answers you need. Thank you for visiting, and see you next time for more valuable insights.