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Which is the equation of the line with slope 3 that contains point (-1,5)?


y-1 = 3(x + 5)
y - 1 = 3(x - 5)
y - 5= 3(x - 1)
y - 5= 3(x + 1)

Sagot :

the answer is y-5=3(x+1)
Abiafalak8idn

Answer:

D

[tex]y-5=3(x+1)[/tex]

Step-by-step explanation:

We can see that the question is asking for the Point-Slope Form;

[tex]y-y_{1} =m(x-x_{1})[/tex]

The points go into the equation for [tex]y_{1}[/tex] and [tex]x_{1}[/tex]

[tex]y-5=m[x-(-1)][/tex]

M would be the slope;

[tex]y-5=3[x-(-1)][/tex]

Which basically is:

[tex]y-5=3(x+1)[/tex]

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