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Assign an oxidation number to each element in the reaction. co(g) 2h2(g) → ch3oh(g) in co, the oxidation number of c is , and that of o is . in h2, the oxidation number of h is . in ch3oh, the oxidation number of c is , that of o is , and that of h is .

Sagot :

The oxidation state is the number of electrons gained and donated. The oxidation state of C is +2, O is -2, H is 0, and in methanol, C is +1, H is +1, and O is -2.

What is the oxidation number?

The oxidation number denotes the number of electrons donated and gained after the bond formation. In general, the oxidation state of free elements is zero, and of hydrogen when the bond to non-metal is +1 and with metals is -1.

The chemical reaction is given as,

[tex]\rm CO + 2H_{2} \rightarrow CH_{3}OH[/tex]

Here,

The oxidation number of carbon in carbon monoxide will be +2, and oxygen will be -2.

The oxidation number of hydrogen in dihydrogen will be zero, and in methanol, the oxidation number of carbon will be +1, hydrogen will be +1 and oxygen will be -2.

Therefore, the oxidation number of oxygen is -2 most of the time.

Learn more about oxidation numbers here:

https://brainly.com/question/16326344

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