Answered

IDNLearn.com offers a user-friendly platform for finding and sharing answers. Find the answers you need quickly and accurately with help from our knowledgeable and dedicated community members.

What is the energy required to remove the electron from a hydrogen atom in the n = 11 state?

Sagot :

Mickymike92idn

Based on the data given, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

What is ionization energy?

Ionization energy is the energy requiredto remove an electron from a neutral atom or a cation in its gaseous state.

To calculate the energy required to remove the electron from a hydrogen atom in the n = 11 state, the formula below is used:

  • [tex]E_n = \frac{E_0 × Z^{2}}{n^{2}}[/tex]

where

[tex]E_0 \: is \: ground \: state \: energy \: of \: hydrogen \: atom \: = -13.6 eV \\ [/tex]

  • Z = 1
  • n = 11

substituting the values:

[tex]E_n = \frac{ - 13.6 × 1^{2}}{11^{2}} \: = - 0.112 \: eV[/tex]

Therefore, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

Learn more about ionization energy at: https://brainly.com/question/1445179

Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Discover insightful answers at IDNLearn.com. We appreciate your visit and look forward to assisting you again.