Answered

Explore a vast range of topics and get informed answers at IDNLearn.com. Explore thousands of verified answers from experts and find the solutions you need, no matter the topic.

What is the energy required to remove the electron from a hydrogen atom in the n = 11 state?

Sagot :

Mickymike92idn

Based on the data given, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

What is ionization energy?

Ionization energy is the energy requiredto remove an electron from a neutral atom or a cation in its gaseous state.

To calculate the energy required to remove the electron from a hydrogen atom in the n = 11 state, the formula below is used:

  • [tex]E_n = \frac{E_0 × Z^{2}}{n^{2}}[/tex]

where

[tex]E_0 \: is \: ground \: state \: energy \: of \: hydrogen \: atom \: = -13.6 eV \\ [/tex]

  • Z = 1
  • n = 11

substituting the values:

[tex]E_n = \frac{ - 13.6 × 1^{2}}{11^{2}} \: = - 0.112 \: eV[/tex]

Therefore, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

Learn more about ionization energy at: https://brainly.com/question/1445179

Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.