Answered

IDNLearn.com makes it easy to find accurate answers to your questions. Our experts are available to provide accurate, comprehensive answers to help you make informed decisions about any topic or issue you encounter.

What is the energy required to remove the electron from a hydrogen atom in the n = 11 state?

Sagot :

Mickymike92idn

Based on the data given, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

What is ionization energy?

Ionization energy is the energy requiredto remove an electron from a neutral atom or a cation in its gaseous state.

To calculate the energy required to remove the electron from a hydrogen atom in the n = 11 state, the formula below is used:

  • [tex]E_n = \frac{E_0 × Z^{2}}{n^{2}}[/tex]

where

[tex]E_0 \: is \: ground \: state \: energy \: of \: hydrogen \: atom \: = -13.6 eV \\ [/tex]

  • Z = 1
  • n = 11

substituting the values:

[tex]E_n = \frac{ - 13.6 × 1^{2}}{11^{2}} \: = - 0.112 \: eV[/tex]

Therefore, the energy required to remove an electron from a hydrogen atom in the n = 11 state is -0.112 eV

Learn more about ionization energy at: https://brainly.com/question/1445179

We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. Thank you for trusting IDNLearn.com. We’re dedicated to providing accurate answers, so visit us again for more solutions.