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The average rates of change of a function f(x) and g(x) are their slopes
The average rate of change of the function f(x) is always less than the average rate of change of the function g(x)
The average rate of change of a function f(x) over the interval [a,b] is calculated as:
[tex]m = \frac{f(b) - f(a)}{b - a}[/tex]
The average rates of change of the functions over the intervals are:
A. 0 ≤ x ≤ 3
[tex]m_1 = \frac{f(3) - f(0)}{3 - 0} = \frac{5 * 3 - 5 *0}{3 - 0} = 5[/tex] ---- f(x)
[tex]m_2 = \frac{g(3) - g(0)}{3 - 0} = \frac{25 * 3 - 25 *0}{3 - 0} = 25[/tex] --- g(x)
B. 0 ≤ x ≤ 2
[tex]m_1 = \frac{f(2) - f(0)}{2 - 0} = \frac{5 * 2 - 5 *0}{2 - 0} = 5[/tex] ---- f(x)
[tex]m_2 = \frac{g(2) - g(0)}{2 - 0} = \frac{25 * 2 - 25 *0}{2 - 0} = 25[/tex] --- g(x)
C. 3 ≤ x ≤ 6
[tex]m_1 = \frac{f(6) - f(3)}{6 - 3} = \frac{5 * 6 - 5 *3}{6 - 3} = 5[/tex] ---- f(x)
[tex]m_2 = \frac{g(6) - g(3)}{6 - 3} = \frac{25 * 6 - 25 *3}{6 - 3} = 25[/tex] --- g(x)
D. 1 ≤ x ≤ 2
[tex]m_1 = \frac{f(2) - f(1)}{2 - 1} = \frac{5 * 2 - 5 *1}{2 - 1} = 5[/tex] ---- f(x)
[tex]m_2 = \frac{g(2) - g(1)}{2 - 1} = \frac{25 * 2 - 25 *1}{2 - 1} = 25[/tex] --- g(x)
From the above computation, we can see that:
The average rate of change of the function f(x) = 5x is always less than the average rate of change of the function g(x) = 25x
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