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A bag of fruit contains 3 apples, 2 oranges, 1 banana, and 4 pears, Gerald will randomly select two pieces of fruit
one at a time from the bag and not put them back. What is the probability that the first piece of fruit Gerald selects will be a banana and the second piece of fruit will be a pear?

Sagot :

Answer:

2/45

Step-by-step explanation:

The probability that a banana is picked for the first one is:

1/10

because there are 10 fruits and one of them is a banana,

Then, the second piece has to be a pear.

For this we have already picked one fruit out of the bag, which leaves 9 fruits in the bag.

There are 4 pears so the probability of picking a pear second is

4/9

To find the probability of a banana and then a pear, you want to multiply these values together

So:

1/10 x 4/9 = 4/90 = 2/45

So the probability is 2/45

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