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Solve |y + 2|>6

A. {y|y<-8 or y>4}

B. {y|y<-6 or y>6}

C. {y|y<-4 or y>4}

Sagot :

Answer:

[tex]y < -8[/tex]

[tex]y > 4[/tex]

Step-by-step explanation:

Absolute Value Inequality entered :

     |y+2|>6

Step by step solution :
Step 1: Rearrange this Absolute Value Inequality

Absolute value inequalitiy entered

     |y+2| > 6

Step 2: Clear the Absolute Value Bars

Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.

The Absolute Value term is |y+2|

For the Negative case we'll use -(y+2)

For the Positive case we'll use (y+2)

Step 3: Solve the Negative Case

     -(y+2) > 6

    Multiply

     -y-2 > 6

    Rearrange and Add up

     -y > 8

    Multiply both sides by (-1)

    Remember to flip the inequality sign

     y < -8

    Which is the solution for the Negative Case

Step 4: Solve the Positive Case

     (y+2) > 6

    Rearrange and Add up

     y > 4

    Which is the solution for the Positive Case

Step 5:

Wrap up the solution

 y < -8

 y > 4

Solutions in Interval Notation

   (-∞,-8)

   (4,+∞)

Solutions on the Number Line

 

Two solutions were found :

 y > 4

 y < -8

View image Аноним
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