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Find a linear equation with two variables that, together with the
equation 10x + 5y = 1, would comprise a system
without a solution.


Sagot :

Answer:

10x+5y=2

Step-by-step explanation: You have the equation 10x+5y=1 and from the problem, we are trying to find an equation that does not produce a solution with 10x+5y=1. To do this know 1 is your y-intercept and if you put 10x+5y=1 into slope-intercept form you'll get y=-2x+1/5. Solve the problem know that you can use any number besides 1 on the right side and have the same slope to fit the question. What I mean is that let's say I have 10x+5y=2, I put it into a slope-intercept form I'll have y=-2x+2/5. The two equations y=-2x+1/5 and y=-2+2/5 will not meet because their slopes are PARALLEL. So in short have a different y-intercept but the same slope to not get a solution. Additional note you could have other y-intercepts such as 3,4,5,6,7,8, or 9 in your standard form equation 10x+5y= to get a equation that does not make a solution with 10x+5y=1.