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The sum of three consecutive, positive, even integers is 18
more than twice the smallest. The integers are_____.


Sagot :

Answer:

5, 6, 7

Step-by-step explanation:

5 + 6 + 7 = 18

Answer:

15,16,17

Step-by-step explanation:

The question states, The sum of three consecutive, positive, even integers is 18 more than twice the smallest.

Let a,b,c be positive integers

Let a be the smallest integer.

Because the answer says the sum of the integers has to be 18 more than   2 x  the smallest integer. It means the situation can be represented as:

a + b + c = 2a + 18

Because these numbers are consecutive, meaning they are right besides each other. Every variable can be written in terms of a.

a = a

b = a + 1

c = a + 2

Now we can solve for a:

a + (a+1) + (a+2) = 2a + 18

a + a + 1 + a + 2 = 2a + 18

3a + 3 = 2a + 18

a + 3 = 18

a = 15

then we can fill in the rest.

b = (15) + 1 = 16

c = (15) + 2 = 17

Now we verify.

15 + 16 + 17 = 2(15) + 18 ?

15 + 16 + 17 = 48

2(15) + 18 = 48

We now have the solution. The consecutive numbers, are, and can only be

15,16,17