Answer:
-58/7
Step-by-step explanation:
Alright so this is a system of equations. First we'll solve the system, and then find the ratio afterwards.
[tex]3x-5y = 11\\2x+3y =5\\[/tex]
Isolate for y on both.
[tex]2x + 3y = 5\\3y = 5-2x\\y = \frac{5-2x}{3}[/tex]
and
[tex]3x - 5y = 11\\-5y = 11-3x\\y = \frac{11-3x}{-5}[/tex]
Set both equations equal to each other:
[tex]\frac{11-3x}{-5} = \frac{5-2x}{3}\\ \\\frac{3(11-3x)}{-5} = 5-2x\\ \\3(11-3x) = -5(5-2x)\\\\33 - 9x = -25 + 10x\\33 = -25 + 19x\\58 = 19x\\\frac{58}{19} = x[/tex]
We've got x, now let's solve for y:
[tex]y = \frac{11-3x}{-5} = \frac{11-3(\frac{58}{19}) }{-5}[/tex]
Now we got both x and y, and what they equal.
[tex]y = \frac{-7}{19}\\[/tex]
[tex]x = \frac{58}{19}[/tex]
The ratio of x to y, is essentially [tex]\frac{x}{y}[/tex]. So we will calculate that.
[tex]\frac{\frac{58}{19} }{\frac{-7}{19} } = \frac{58}{19} * \frac{19}{-7} = \frac{-58}{7}[/tex]
