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73.5 mol of P4O10 contains how many moles of P ? moles of P:

Sagot :

Answer:

294 moles of P

Explanation:

For every 1 mol of P4O10 contains 4 mol of P

so;

73.5 mol P4O10 × 4 mol P

1 mol P4O10

= 73.5 × 4

= 294 moles of P