Answer:
a) 5, -3, -4, 0
b) Curve B
Step-by-step explanation:
Given equation:
[tex]y=x^2-4x[/tex]
Inputting the values of x into the equation to find the missing values of y:
[tex]x=-1 \implies y=(-1)^2-4(-1)=5[/tex]
[tex]x=1 \implies y=(1)^2-4(1)=-3[/tex]
[tex]x=2 \implies y=(2)^2-4(2)=-4[/tex]
[tex]x=4 \implies y=(4)^2-4(4)=0[/tex]
[tex]\large\begin{array}{| c | c | c | c | c | c | c | c |}\cline{1-8} x & -1 & 0 & 1 & 2 & 3 & 4 & 5\\\cline{1-8} y & 5 & 0 & -3 & -4 & -3 & 0& 5\\\cline{1-8}\end{array}[/tex]
According to the table:
- y-intercept of the curve = (0, 0)
- x-intercept of the curve = (4, 0)
Therefore, Curve B matches the graph of [tex]y=x^2-4x[/tex]
