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Find the vertex of this parabola:
y = -4x2 + 8x - 13

Sagot :

Answer:

Below in bold.

Step-by-step explanation:

y = -4x2 + 8x - 13

Divide first 2 terms by -4:-

y = -4(x^2 - 2x) - 13

Convert to vertex form by completing the square:

y = -4[(x - 1)^2 - 1] - 13

y = -4(x - 1)^2 + 4 - 13

y = -4(x - 1)^2 - 9     <---------- Vertex form

y =  a(x -  j)^2 + k       <---------- General form with vertex = (j, k).

So comparing, we see that the vertex is   (1, -9).

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