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a car of mass 850kg hits a crash barrier at a speed of 30m/s . the car stops in 0.4s.calculate the force of the car.​

Sagot :

Given :-

  • Mass of Car = 850 kg
  • initial speed,u = 30 m/s
  • Time span in which car stop = 0.4 s

To Find :-

  • force on car

Solution:-

During the collision an impulse is created which due to which is equal to change in momentum.

Mathematically,

[tex]\green{ \underline { \boxed{ \sf{Impulse, F\times t = m (v-u) }}}}[/tex]

where

  • F = force
  • t = time span
  • m = mass
  • v= final speed
  • u = initial speed

Now,

[tex]\begin{gathered}\\\implies\quad \sf F \times 0.4 = 850 \times (0-30) \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf F \times 0.4 = 850 \times -30 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf F = -\frac{25500}{0.4} \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf F = -63750 N \\\end{gathered} [/tex]

[tex]\quad\quad\quad\quad\quad\quad[/tex](-ve sign denotes opposite direction)

Therefore, a force of 63750 Newton will act on the car in opposite direction.