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Sample data from titration lab:
Amount of analyte; (HCI): 19.54 mL
Amount of titrant: (NaOH): 12.33mL
Molar concentration of NaOH: 0.5 mol
The molarity of the HCl would be:
VM
The numbers I used are probably wrong

Sample Data From Titration Lab Amount Of Analyte HCI 1954 ML Amount Of Titrant NaOH 1233mL Molar Concentration Of NaOH 05 Mol The Molarity Of The HCl Would Be V class=

Sagot :

Mickymike92idn

Based on the volumes of HCl and NaOH reacted, the molarity of HCl is 0.3 M

What a titration?

A titration is a process in volumetric analysis in which the given volume of a substance of known concentration reacting with a volume another solution of unknown concentration is used to determine the unknown concentration of another solution

In the titration given, an unknown concentration of HCl reacts with 0.5 M NaOH solution.

The equation of the reaction is given below:

  • HCl + NaOH -----> NaCl + H2O

At equivalence point, 1 mole of HCl reacts with 1 moles of NaOH

moles of NaOH = 12.33 × 0.5 = 6.165 moles

moles of HCl = 19.54 × M

From above, moles of HCl = 6.165 moles

Molarity of HCl, M = 6.165/19.54

Molarity of HCl = 0.3 M

Therefore, the molarity of HCl is 0.3 M

Learn more about molarity at: https://brainly.com/question/17138838

Answer:

0.317

Explanation:

right on edge

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