Calex08idn
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Linandrew41idn

Steps to finding the line in the diagram with the format 'ax + by = c

1. Find the slope

  • To find the slope, we need any two points on the line --> (0,4) and (3,0)

                  [tex]Slope = \frac{y2-y1}{x2-x1} =\frac{4-0}{0-3} =-\frac{4}{3}[/tex]

2. Set up, with any one point on the line and the slope, in point-slope form

   

        [tex](y-y0)=m(x-x0)\\(y-4)=-\frac{4}{3} (x-0)\\y-4 = -\frac{4}{3} x\\\frac{4}{3}x+y = 4[/tex]

Answer: [tex]\frac{4}{3}x+y = 4[/tex]

Hope that helps!

Semsee45idn

Answer:

[tex]\sf 4x+3y=12[/tex]

Step-by-step explanation:

Choose two points on the line:

Let [tex]\sf (x_1,y_1)=(0,4)[/tex]

Let [tex]\sf (x_2,y_2)=(3,0)[/tex]

Use the slope formula to find the slope of the line:

[tex]\sf slope(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0-4}{3-0}=-\dfrac43[/tex]

Use the point-slope formula to find the equation of the line:

[tex]\sf y-y_1=m(x-x_1)[/tex]

Substitute values into the formula:

[tex]\sf y-4=-\dfrac43(x-0)[/tex]

Expand the brackets:

[tex]\sf y-4=-\dfrac43x[/tex]

Add 4 to both sides:

[tex]\sf y=-\dfrac43x+4[/tex]

Rearrange into the form [tex]ax+by=c[/tex]

Multiply both sides by 3

[tex]\sf 3y=-4x+12[/tex]

Add 4x to both sides:

[tex]\sf 4x+3y=12[/tex]

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