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A balloon has a volume of 22.4 L at 273 K and 760 mm Hg. What will be the new volume if the pressure is
doubled to 2.00 atm?

Sagot :

Onyebuchinnajiidn

The new volume of the gas in the balloon when the pressure is doubled is determined as 11.2 L.

General gas equation

The new volume of the balloon is determined by applying general gas equation as shown below

P₁V₁/T₁ = P₂V₂/T₂

Where;

  • P₁ is the initial pressure of the gas = 760 mmHg = 1 atm
  • V₁ is the initial volume of the gas = 22.4 L
  • T₁ is the initial temperature of the gas = 273 K
  • P₂ is the final pressure of the gas = 2 atm
  • T₂ is the final temperature of the gas = 273 K
  • V₂ is the final volume of the gas = ?

[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \\\\V_2 = \frac{P_1V_1T_2}{T_1P_2} \\\\V_2 = \frac{1 \times 22.4 \times 273}{273 \times 2} \\\\V_2 = 11.2 \ L[/tex]

Thus, the new volume of the gas in the balloon when the pressure is doubled is determined as 11.2 L.

Learn more about general gas equation here: https://brainly.com/question/4147359

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