Seayelana3idn
Answered

Discover new knowledge and insights with IDNLearn.com's extensive Q&A database. Join our Q&A platform to access reliable and detailed answers from experts in various fields.

compound has a percent composition of 38.7% carbon, 9.76% hydrogen, 51.5% oxygen.
Laboratory data shows that the compound's molar mass is 62.0 g/mol. What is the
molecular formula of the compound?

Sagot :

Dsdrajlinidn

The molecular formula for a compound with a percent composition of 38.7% C, 9.76% H, 51.5% O, and a molar mass of 62.0 g/mol is C₂H₆O₂.

What is a molecular formula?

A molecular formula is a chemical formula indicating the kinds and number of atoms of each kind in a molecule of a compound.

To determine the molecular formula, we need to follow a series of steps.

  • Step 1. Divide the percentage of each element by its molar mass.

C: 38.7/12.01 = 3.22

H: 9.76/1.01 = 9.66

O: 51.5/16.00 = 3.22

  • Step 2. Divide all the numbers by the smallest one, i.e. 3.22.

C: 3.22/3.22 = 1

H: 9.76/3.22 = 3

O: 3.22/3.22 = 1

The empirical formula is CH₃O and its molar mass is 31.04 g/mol.

  • Step 3. Determine the molecular formula.

First, we will calculate how many times the empirical formula is contained in the molecular formula by dividing their molar masses.

n = (62.0 g/mol) / (31.04 g/mol) = 2

The molecular formula is 2 times the empirical formula, that is, C₂H₆O₂.

The molecular formula for a compound with a percent composition of 38.7% C, 9.76% H, 51.5% O, and a molar mass of 62.0 g/mol is C₂H₆O₂.

Learn more about molecular formulas here: https://brainly.com/question/26388921

Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. IDNLearn.com is your source for precise answers. Thank you for visiting, and we look forward to helping you again soon.