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Sagot :
now, this is assuming the 6% is at simple interest rate.
[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$2000\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ t=years\dotfill &19 \end{cases} \\\\\\ A=2000[1+(0.06)(19)]\implies A=2000(1.54)\implies A=3080 \\\\[-0.35em] ~\dotfill[/tex]
[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$4000\\ P=\textit{original amount deposited}\dotfill & \$2000\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ t=years \end{cases} \\\\\\ 4000=2000[1+(0.06)(t)]\implies \cfrac{4000}{2000}=1.06t \\\\\\ 2=1.06t\implies \cfrac{2}{1.06}=t\implies 1.89\approx t\implies \stackrel{\textit{rounded up}}{2\approx t}[/tex]
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