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Answer:
Step-by-step explanation:
x³+23x²+162x+360=0
x³+12x²+11x²+132x+30x+360=0
x²(x+12)+11x(x+12)+30(x+12)=0
(x+12)(x²+11x+30)=0
(x+12)[x²+6x+5x+30]=0
(x+12)[x(x+6)+5(x+6)]=0
(x+12)(x+6)(x+5)=0
x=-12,-6,-5