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Sagot :
The probability of winning when there is only one prize, is:
P = 1/2,790,720
How to find the probability?
Each ticket has 6 different numbers, in order, from 1 to 20.
- The first number has 20 options.
- The second number has 19 options (because the numbers can't repeat).
- The third number has 18 options, and so on.
The total number of possible combinations is given by the product between the numbers of options, so there are:
C = 20*19*18*17*16*15 = 27,907,200 possible tickets.
So, if Trina purchases 10 tickets, she has a probability of 10 out of 27,907,200 winning (when we assume that there is only one prize)
Then the probability is:
P = 10/27,907,200 = 1/2,790,720
If you want to learn more about probability, you can read:
https://brainly.com/question/251701
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