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R\ {0}→→ Ris defined by Jff: 1 f(x)=x³-1/x³-1then show that 2 f(x) + f(1/x)=0.
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Sagot :

[tex]\orange\bigstar \bold{ solution}[/tex]

[tex]\bold{f(x) = x³ - \frac{1}{x³ } }[/tex]

[tex]\bold{f ( \frac{1}{x} )= \frac{1}{x³} -x³ } [/tex]

[tex]\bold{f (x) + f (\frac{1}{x}) = (x³- \frac{1}{x³} ) + ( \frac{1}{x³} -x³)}[/tex]

[tex]\bold{ = 0 }[/tex]

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