IDNLearn.com provides a collaborative environment for finding and sharing answers. Ask anything and receive prompt, well-informed answers from our community of experienced experts.
Sagot :
The probability that a worker chosen at random works at least 8 hours is Option C: 0.84 approx.
How to evaluate the probability of a random variable getting at least some fixed value?
Suppose the random variable in consideration be X, and it is discrete.
Then, the probability of X attaining at least 'a' is written as:
[tex]P(X \geq a)[/tex]
It is evaluated as:
[tex]P(X \geq a) = \sum_{\forall \: x_i \geq a} P(X = x_i)[/tex]
The probability distribution of X is:
x f(x) = P(X = x)
6 0.02
7 0.11
8 0.61
9 0.15
10 0.09
Worker working at least 8 hours means X attaining at least 8 as its values.
Thus, probability of a worker chosen at random working 8 hours is
P(X ≥ 8) = P(X = 8) + P(X = 9) +P(X = 10) = 0.85 ≈ 0.84 approx.
By the way, this probability distribution seems incorrect because sum of probabilities doesn't equal to 1.
The probability that a worker chosen at random works at least 8 hours is Option C: 0.84 approx.
Learn more about probability distributions here:
https://brainly.com/question/14882721
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! For clear and precise answers, choose IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.