IDNLearn.com provides a collaborative environment for finding and sharing answers. Our Q&A platform offers reliable and thorough answers to help you make informed decisions quickly and easily.
Based on the calculations, the radius of this circle with the given equation is equal to 5 units.
Given the following data:
Mathematically, the standard form of the equation of a circle is given by;
[tex](x-h)^2+(y-k)^2=r^2[/tex]
Where:
Expanding the equation, we have:
[tex]x^2+y^2-2hx-2ky+(h^2+k^2-r^2)=0\\\\r=\sqrt{h^2+k^2}[/tex]
Comparing the terms, we have:
[tex]-2hx = 8x\\\\-2h=8\\\\h=\frac{8}{-2}[/tex]
h = -4
[tex]-2ky = -6y\\\\-2k=6\\\\k=\frac{6}{-2}[/tex]
k = 3.
Now, we can determine the radius:
[tex]r=\sqrt{-4^2+3^2}\\\\r=\sqrt{16+9} \\\\r=\sqrt{25}[/tex]
r = 5 units.
Read more on circle here: https://brainly.com/question/14078280