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Each side of the square below is 8 inches. A triangle inside of a square. The top of the triangle divides a side of the square into 2 equal parts of 4 inches. The triangle is shaded and the area to the right of the triangle is shaded. What is the probability that a point chosen at random in the square is in the blue region? 0. 25 0. 33 0. 66 0. 75.

Sagot :

The probability that a point is chosen at random in the square is in the blue region is 0.8.

What is Probability?

The probability helps us to know the chances of an event occurring.

[tex]\rm{Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]

As we know that the area of the shaded region is the sum of the area of triangle A and the area of triangle B. Therefore, the area of the blue shaded region is,

[tex]\text{Area of shaded region} = (\dfrac{1}{2} \times 8 \times 8) + (\dfrac{1}{2} \times 4 \times 8)[/tex]

                                  [tex]= (32) + (16)\\\\= 48\rm\ in^2[/tex]

The area of the square can be written as,

[tex]\text{Area of Square} = \rm(Side)^2 = 8^2 = 64\ in^2[/tex]

Now, the probability that a point is chosen at random in the square is in the blue region can be written as,

[tex]\rm{Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}\\\\[/tex]

[tex]\rm Probability = \dfrac{\text{Area of blue region}}{\text{Area of square}}\\\\Probability = \dfrac{48}{60} = 0.8[/tex]

Hence, the probability that a point is chosen at random in the square is in the blue region is 0.8.

Learn more about Probability:

https://brainly.com/question/795909

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