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A nitrogen bubble with a volume of 0.0050 mL forms in the joint of a scuba diver as she ascends rapidly from a pressure of 4.1 atm to the surface, with a pressure of 1.0 atm. What is the volume of the bubble at the surface

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Nuhulawal20idn

As the scuba diver ascends rapidly to the surface at the given pressure, the volume of the nitrogen bubble at the surface becomes 0.021mL.

Boyle's law

Boyle's law states that the volume V of a given quantity of gas is inversely proportional to its pressure P as long as temperature remains constant.

Boyle's law is expressed as;

P₁V₁ = P₂V₂

Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.

Given the data in the question;

  • Initial volume; V₁ = 0.005mL = 5.0 × 10⁻⁶L
  • Initial pressure; P₁ = 4.1atm
  • Final pressure; P₂ = 1.0atm  
  • Final volume; V₂ = ?

We substitute our given values into the expression above to find the final volume.

P₁V₁ = P₂V₂

[tex]V_2 = \frac{P_1V_1}{P_2} \\\\V_2 = \frac{4.1atm \ *\ 5.0*10^{-6}L}{1.0atm}\\ \\V_2 = \frac{4.1 \ *\ 5.0*10^{-6}L}{1.0}\\\\V_2 = 2.05*10^{-6}L\\\\V_2 = 0.021mL[/tex]

Therefore, as the scuba diver ascends rapidly to the surface at the given pressure, the volume of the nitrogen bubble at the surface becomes 0.021mL.

Learn more about Boyle's law: brainly.com/question/1437490

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