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When the triangle XYZ is dilated by a scale factor of 4/3, the resulting triangle would have a bigger side lengths
The algebraic rule is [tex](x,y) \to (\frac 43x,\frac 43y)[/tex]
From the question, we understand that:
The scale factor (k) of the dilation is:
k = 4/3
The dilation rule across the origin is represented as:
[tex](x,y) \to k(x,y)[/tex]
Substitute 4/3 for k
[tex](x,y) \to \frac 43(x,y)[/tex]
Expand
[tex](x,y) \to (\frac 43x,\frac 43y)[/tex]
Hence, the algebraic rule that represents how to find the coordinates of triangle X’Y’Z’ is [tex](x,y) \to (\frac 43x,\frac 43y)[/tex]
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