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Four interior angles of a pentagon measure 88°, 118°, 132°, and 100°. What is the measure of the fifth interior angle? 82° 92° 102° 112°.

Sagot :

the sum of all interior angles in a polygon is

180( n - 2), n = number of sides

we know this one is a PENTAgon, so it has 5 sides, so the total for the interior angles will be

180( 5 - 2) = 540 degrees.

540° - 88° - 118° - 132° - 100° = 102° <- fifth angle.

Facundo3141592idn

The final interior angle of the pentagon measures 102°.

What is the measure of the fifth interior angle?

We know that for a figure of n sides, the sum of its interior angles is equal to:

S = (n - 2)*180°

Then for a pentagon, 5 sides, we have:

S = (5 - 2)*180° = 3*180° = 540°

Then if X is the missing interior angle, we must have:

88° + 118° + 132° + 100° + X = 540°

438° + X = 540°

X = 540° - 438° = 102°

So the measure of the last interior angle is 102°.

If you want to learn more about interior angles:

https://brainly.com/question/24839702

#SPJ2

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