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1. What is the distance covered by a T-Rex that goes from 0 m/s to 9 m/s in 6.78 seconds? (10
points)

Sagot :

Temdan2001idn

With the use of first and third equation of motion, the distance covered by a T-Rex is 30.51 m

Linear Motion

When a body is in linear motion, the body is moving in a straight line. some of the parameters to consider are:

  • Distance covered
  • Speed
  • Velocity
  • Acceleration
  • E.T.C

Given that a T-Rex move from 0 m/s to 9 m/s in 6.78 seconds, the distance covered can be found by calculating the acceleration.

Let us use equation 1

V = U + at

9 = 0 + 6.78a

a = 9 / 6.78

a = 1.33 m/[tex]s^{2}[/tex]

Now let us use equation 3

[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as

[tex]9^{2}[/tex] = 2 x 1.33 x S

81 = 2.655S

S = 81/2.655

S = 30.51 m

Therefore, the distance covered by a T-Rex is 30.51 m.

Learn more about Linear Motion here: https://brainly.com/question/12721831

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