Answered

Get the answers you've been looking for with the help of IDNLearn.com's expert community. Ask any question and receive comprehensive, well-informed responses from our dedicated team of experts.

14. Calculate the mass in grams of oxygen required to react completly with 0.75 moles of Aluminum.
4Al + 302 → 2Al2O3
a. 32 g of Oxygen
b. 18 g of Oxygen
c. 16 g of Oxygen
d. 9.0 g of Oxygen

Sagot :

  • 3mols of O_2 react with 4mol of Al
  • 3/4=0.75mol O_2 react with 1mol of Al

Moles of O_2:-

  • 0.75(0.75)
  • 0.5625mol

Mass of O_2:-

  • moles(Molar mass)
  • 0.5625(32)
  • 18g

Option B

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. IDNLearn.com provides the answers you need. Thank you for visiting, and see you next time for more valuable insights.