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Find the length of x in the 45 degree, -45 degree, -90 degree triangle. Show work

Find The Length Of X In The 45 Degree 45 Degree 90 Degree Triangle Show Work class=

Sagot :

Chibabykalu16idn

Answer:

Option A

Step-by-step explanation:

Given:

  • Angle=45°
  • Base= 9
  • hypotenuse = x

[tex] \sf \therefore \: cos \: 45 \degree = \frac{base}{hypotenuse} = \frac{9}{x} [/tex]

[tex] \sf \cos(45 \degree) = \frac{1}{ \sqrt{2} } [/tex]

[tex] \sf \frac{1}{ \sqrt{2} } = \frac{9}{x} [/tex]

[tex] \therefore \: \rm \: x = 9 \sqrt{2} [/tex]

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