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Sagot :
hello!
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Perpendicular lines have slopes that are opposite reciprocals.
This means we take the slope, flop it over, and change its sign.
In this case, we have
[tex]\boxed{-4}[/tex]
First, flop it over:
[tex]\boxed{-\frac{1}{4}}[/tex]
Change its sign:
[tex]\boxed{\frac{1}{4}}[/tex]
Now, let's write the equation of the line in point-slope form:-
[tex]\bigstar\boxed{\pmb{y-y1=m(x-x1)}}\longleftarrow\sf{Point-Slope~Formula}[/tex]
Where
y₁ is the y-coordinate of the point that the line intersects
m is the slope of the line
x₁ is the x-coordinate of the point that the line intersects
In this case,
y₁ is equal to -4
m is equal to [tex]\boxed{\frac{1}{4} }[/tex]
x₁ is equal to -2
Plug in the values:-
[tex]\bigstar{\boxed{y-(-4)=\frac{1}{4}(x-(-2)}[/tex]
Simplify:-
[tex]\longrightarrow\sf{y+4=\frac{1}{4} (x+2)[/tex]
and we're done!
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note:-
Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)
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