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Two sides of a triangle measure 17 inches and 13 inches. The perimeter of the triangle is 45 inches. What is the length in feet of the third side of the triangle?​

Sagot :

Given:-

[tex]\rightarrow[/tex] First side(a) of triangle = 17in.

[tex]\rightarrow[/tex] Second side(b) of triangle = 13in.

[tex]\rightarrow[/tex] Perimeter of triangle = 45in.

To Find:-

[tex]\rightarrow[/tex]Third side of the triangle.

Formula Used:-

[tex]\rightarrow[/tex] Perimeter of triangle = sum of all side(a+b+c).

Solution:-

[tex]\rightarrow[/tex] Perimeter of triangle = a + b + c.(putting the value of perimeter, side a and b from the above given)

[tex]\rightarrow[/tex] [tex]\sf{45\: = \: 17+13+c}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{45\: = \: 30+c}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{45-30\: = \:c}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{15in.\: = \: c}[/tex]

Therefore, third side = 15in.

[tex]\rightarrow[/tex]To convert this value into feet we need to divide it by 12, because there are 12 inches in a foot.

[tex]\rightarrow[/tex] [tex]\sf{\frac{15}{12}}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{1.25feet}[/tex]

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Hope it helps you:)

Answer:

Side 3 = 1.25 feet

Step-by-step explanation:

Given :

  • Two side measures of a triangle = 17 inches and 13 inches
  • Perimeter = 45 inches

To Find :

  • Length of 3rd side

Solving :

  • Side 1 + Side 2 + Side 3 = Perimeter
  • 13 + 17 + Side 3 = 45
  • Side 3 = 45 - 30
  • Side 3 = 15 inches
  • Side 3 = 1.25 feet