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Based on the calculations, the temperature of this ideal gas is equal to 300.5 K.
Mathematically, the temperature of an ideal gas is given by this formula:
[tex]PV=nRT\\\\T=\frac{PV}{nR}[/tex]
Where:
Given the following data:
Number of moles = 12.20 moles.
Volume = 18.35 L.
Pressure = 16.40 atm.
Substituting the given parameters into the formula, we have;
[tex]T=\frac{16.40 \times 18.35}{12.20 \times 0.0821}\\\\T=\frac{300.94}{1.00162}[/tex]
T = 300.5 K.
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