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Using the law of sine on the given triangle, we get the measure of y as given by: Option C: 2.5 units
For any triangle ABC, with side measures |BC| = a. |AC| = b. |AB| = c,
we have, by law of sines,
[tex]\dfrac{\sin\angle A}{a} = \dfrac{\sin\angle B}{b} = \dfrac{\sin\angle C}{c}[/tex]
Remember that we took
[tex]\dfrac{\sin(angle)}{\text{length of the side opposite to that angle}}[/tex]
For this case, the missing image is attached below.
Applying the sine law, as we have:
The first two angles Y and Z are enough. (we use angle Z as the length of the side opposite to Z is known).
Using sine law, we get:
[tex]\dfrac{\sin(m\angle Y)}{y} = \dfrac{\sin(m\angle Z)}{2}\\\\y = \dfrac{\sin(75^\circ) \times 2}{\sin(50^\circ)} \approx 2.522 \approx 2.5 \: \rm units[/tex]
Thus, using the law of sine on the given triangle, we get the measure of y as given by: Option C: 2.5 units
Learn more about law of sines here:
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