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The percent yield of CuO is 96%. The percentage yield shows the extent to which reactants are converted to products.
The percent yield is the actual yield divided by the theroretical yield multiplied by 100.
Now we have the equation;
2Cu(OH)2 → 2CuO + 2H2O
Number of moles of Cu(OH)2 = 6.59 g/98 g/mol = 0.067 moles
Since 2 mole of Cu(OH)2 yeilds 2 moles of CuO
0.067 moles alos yields 0.067 moles of CuO
Mass of CuO = 80 g/mol * 0.067 moles of CuO = 5.36 g
Hence, percent yield = 5.17 g/5.36 g * 100 = 96%
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