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Write the equation in standard form for the circle with center (0, -5) and radius 2

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Linandrew41idn

The standard equation for a circle is '[tex](x-h)^2+(y-k)^2=r^2[/tex]

  • (h,k): coordinate for the center of the circle              --> (0,-5)
  • r: radius                                                                        --> 2

      --> Standard form:

              [tex](x - )^2 +(y-(-5))^2=2^2\\x^2+(y+5)^2=4[/tex]

Hope that helps!

Answer:

x^2 + (y + 5)^2 = 4.

Step-by-step explanation:

Standard form is (x - a)^2 + (y - b)^2 = r^2

 - where (a, b) is the center and radius = r.

So our equation is:

(x - 0)^2 + (y - (-5))^2 = 2^2

x^2 + (y + 5)^2 = 4.

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