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Answer:
[tex]\frac{dy}{dx}=-\frac{x}{y}[/tex]
Step-by-step explanation:
Use implicit differentiation:
[tex]x^2+y^2=25\\\\2x+2y\frac{dy}{dx}=0\\ \\2y\frac{dy}{dx}=-2x\\ \\\frac{dy}{dx}=-\frac{x}{y}[/tex]
Remember to treat "y" as a constant in implicit differentiation and include dy/dx.