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Sagot :
Given the data from the question, the heat gained by the water, the rate of energy transfer and the initial temperature of the iron are:
A. The energy gained by the water is 37656 J
B. The average rate of energy transfer from
the iron sphere to the water is 125.52 J/s (Watts)
C. The initial temperature of the iron
sphere is 65.4° C
A. How to determine the heat gained
- Mass of water (M) = 3 Kg = 3 × 1000 = 3000 g
- Initial temperature (T₁) = 12 °C
- Final temperature (T₂) = 15 °
- Change in temperature (ΔT) = 15 – 12 = 3 °C
- Specific heat capacity (C) = 4.184 J/gºC
- Heat (Q) =?
Q = MCΔT
Q = 3000 × 4.184 × 3
Q = 37656 J
B. How to determine the rate of energy transfer
- Heat (Q) = 37656 J
- Time (t) = 5 min = 5 × 60 = 300 s
- Power (P) =?
Power = energy / time
Power = 37656 / 300
Power = 125.52 J/s (Watts)
C. How to determine the initial temperature of the iron
- Mass of iron (M) = 1.2 Kg = 1.2 × 1000 = 1200 g
- Heat capacity (C) = 576 J/ºC
- Heat (Q) = 37656 J
- Temperature (T) =?
Q = CT
37656 = 576 × T
Divide both side by 576
T = 37656 / 576
T = 65.4° C
Learn more about heat transfer:
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