Answered

Explore a vast range of topics and get informed answers at IDNLearn.com. Our platform offers reliable and detailed answers, ensuring you have the information you need.

A truck with a mass of 4285 kg is moving at 9. 35 m/s. it crashes into the rear end of a larger truck with a mass of 5495 kg moving at 6. 35 m/s in the same direction. a. what is the final velocity if the trucks lock together? b. how much does the kinetic energy decrease in the collision?

Sagot :

Onyebuchinnajiidn

(a) The final velocity if the trucks lock together after the collision is 7.66 m/s.

(b) The decrease in the kinetic energy after the collision is 11,165.1 J.

Conservation of linear momentum

The final velocity of the two truck system after the collision is determined by applying the principle of conservation of linear momentum as shown below;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

4285(9.35) + 5495(6.35) = v(4285 + 5495)

74,958 = 9,780v

v = 74,958/9780

v = 7.66 m/s

Initial kinetic energy of the trucks

K.E = ¹/₂mv²

K.Ei = ¹/₂(4285)(9.35)² + ¹/₂(5495)(6.35)²

K.Ei = 298,088.78 J

Final kinetic energy of the trucks

K.Ef = ¹/₂(m₁ + m₂)v²

K.Ef = ¹/₂(4285  + 5495)(7.66)²

K.Ef = 286,923.68 J

Change in kinetic energy

ΔK.E = K.Ef - K.Ei

ΔK.E = 286,923.68 J - 298,088.78 J

ΔK.E = - 11,165.1 J

Learn more about linear momentum here: https://brainly.com/question/7538238

We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your search for answers ends at IDNLearn.com. Thank you for visiting, and we hope to assist you again soon.