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The z-score of the number of teens that transfered schools is the standard score
The obtained value of z is 5
The given parameters are:
The z-value is calculated using:
z = (x - μ)/σ
Substitute known values in the above formula
z = (100 - 50)/10
Evaluate the difference
z = 50/10
Evaluate the quotient
z = 5
Hence, the obtained value of z is 5
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